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7m^2-7092=0
a = 7; b = 0; c = -7092;
Δ = b2-4ac
Δ = 02-4·7·(-7092)
Δ = 198576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{198576}=\sqrt{144*1379}=\sqrt{144}*\sqrt{1379}=12\sqrt{1379}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{1379}}{2*7}=\frac{0-12\sqrt{1379}}{14} =-\frac{12\sqrt{1379}}{14} =-\frac{6\sqrt{1379}}{7} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{1379}}{2*7}=\frac{0+12\sqrt{1379}}{14} =\frac{12\sqrt{1379}}{14} =\frac{6\sqrt{1379}}{7} $
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